You have 10 jars .Each jar has 100 marbles
9 of the 10 jars -> each marble weighs 1 gram each
last jar -> each marble weights 1.1 grams each
electronic weight scale
- place what you want to weight on it
- hit a button
- get the total weight
find the defective jar ?
Answer:Take 1 marble from jar 1, 2 from jar 2, 3 from jar 3 and so on...so u have 55 marbles in all
Weigh them all together...if total weight is 55.1....then jar 1 is the one with obese marbles...if 55.2..then jar 2...and so on... again 55.3 can't be the combination of jar 1 and 2 as (.1 +.2 ) since defective jar is only one.
9 of the 10 jars -> each marble weighs 1 gram each
last jar -> each marble weights 1.1 grams each
electronic weight scale
- place what you want to weight on it
- hit a button
- get the total weight
find the defective jar ?
Answer:Take 1 marble from jar 1, 2 from jar 2, 3 from jar 3 and so on...so u have 55 marbles in all
Weigh them all together...if total weight is 55.1....then jar 1 is the one with obese marbles...if 55.2..then jar 2...and so on... again 55.3 can't be the combination of jar 1 and 2 as (.1 +.2 ) since defective jar is only one.
4 comments:
i can solve in 5 weights.
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1. divide in 2 groups of 5-5 jars(2 weights)
2. select the group with heavy weight and divide in 3 group of 2-2-1.
3. weight the group having 2 jars if both have same weight then ans is the rest 1 jar (2 weight)
4. if weight is not same then select the heavier group and weight any jar.(1 weight)
hence total 5 weights. Is it possible to find out the ans in less than 5 weights ??
Take 1 marble from jar 1, 2 from jar 2, 3 from jar 3 and so on...so u have 55 marbles in all
Weigh them all together...if total weight is 55.1....then jar 1 is the one with obese marbles...if 55.2..then jar 2...and so on...
therefore just 1 weighing...
@anon not true how about reading comes out as 55.3 then its may b combination of 1st and 2nd as (0. +0.2=0.3 ) possible ??
Only one of the jars has heavier marbles, so it cannot be a combination of 1st and 2nd.
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